10주차. solution - 오시영

live

def isBeautifulString(inputString):
    cnts = [0] * 26
    
    for c in inputString: 
        idx = ord(c)-97        
        cnts[idx] += 1
        
    return True if cnts[::-1] == sorted(cnts) else False

test case

testcases = {"bbbaacdafe": True,
             "aabbb": False, 
             "bbc": False, 
             "bbbaa" : False, 
             "abcdefghijklmnopqrstuvwxyzz": False, 
             "abcdefghijklmnopqrstuvwxyz": True, 
             "abcdefghijklmnopqrstuvwxyzqwertuiopasdfghjklxcvbnm": True, 
             "fyudhrygiuhdfeis": False, 
             "zaa": False, 
             "zyy": False,}

def test_solution(testcases) : 
    for t in testcases.keys():
        result = isBeautifulString(t)
        
        if testcases[t] != result:
            print(f"Wrong Case: {t} / expected: {testcases[t]} / your : {result}")
        
    print("Test Finished")

## Refactoring

Refactoring

import string 

def isBeautifulString(inputString):
    cnts = [inputString.count(c) for c in string.ascii_lowercase]

    return cnts[::-1] == sorted(cnts)

python battery included 만세

ref

count occurrence of substring
- https://docs.python.org/3/library/stdtypes.html?highlight=str%20count#str.count
  - Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.
- e.g. https://www.programiz.com/python-programming/methods/string/count
get ascii value
- https://docs.python.org/3/library/functions.html?highlight=ord#ord
  - Given a string representing one Unicode character, return an integer representing the Unicode code point of that character. For example, ord('a') returns the integer 97 and ord('€') (Euro sign) returns 8364. This is the inverse of chr().
- e.g. https://www.programiz.com/python-programming/examples/ascii-character
list comprehension short for loop
- https://stackoverflow.com/questions/6475314/python-for-in-loop-preceded-by-a-variable
- ```
`result = [number for number in numbers if number > 5]`
```
python alphabet ascii code
- https://docs.python.org/3/library/string.html#string.ascii_lowercase
- e.g.
```
import string

print(string.ascii_lowercase) 
# print string "abcdefghijklmnopqrstuvwxyz"
```
  -